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Recursion & Polymorphismλ︎

Fixme work in progress

The following sum function will calculate the value of adding all the elements in a collection. You can alter the results by adding a starting value to the calculation as a second argument when calling sum

(defn sum
  ([vals] (sum vals 0))
  ([vals accumulating-total]
    (if (empty? vals)
      (sum (rest vals) (+ (first vals) accumulating-total)))))

(sum [2 7 9 11 13])
(sum [1])
(sum [2 7 9 11 13] 9)

Rather than duplicate the calculation, the behaviour of calling sum with just a collection simply calls sum again, this time passing a starting value of zero.